Dict(Dict()) 표현

딕셔너리 참고 사이트 

 

fares = [[4, 1, 10], [3, 5, 24], [5, 6, 2], [3, 1, 41], [
    5, 1, 24], [4, 6, 50], [2, 4, 66], [2, 3, 22], [1, 6, 25]]


def solution(fares):
    total = 0
    matrix = {i+1: dict() for i in range(n)}

    for i, j, k in fares:
        matrix[i].update({j: k})
        matrix[j].update({i: k})

    print(matrix)
    print(*matrix.items(), sep='\n')

    return total


solution(n, s, a, b, fares)

>>> {1: {4: 10, 3: 41, 5: 24, 6: 25}, 2: {4: 66, 3: 22}, 3: {5: 24, 1: 41, 2: 22}, 4: {1: 10, 6: 50, 2: 66}, 5: {3: 24, 6: 2, 1: 24}, 6: {5: 2, 4: 50, 1: 25}}

>>> (1, {4: 10, 3: 41, 5: 24, 6: 25})
>>> (2, {4: 66, 3: 22})
>>> (3, {5: 24, 1: 41, 2: 22})       
>>> (4, {1: 10, 6: 50, 2: 66})       
>>> (5, {3: 24, 6: 2, 1: 24})        
>>> (6, {5: 2, 4: 50, 1: 25})